A proton accelerated by a potential difference $500\;KV$ moves though a transverse magnetic field of $0.51\;T$ as shown in figure. The angle $\theta $through which the proton deviates from the initial direction of its motion is......$^o$

131-47

  • A

    ${15}$

  • B

    ${30}$

  • C

    ${45}$

  • D

    ${60}$

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