(A) The equation of motion for a particle starting from rest under a constant electric force is given by $h = \frac{1}{2} a t^2$,where $a = \frac{qE}{

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(A) The equation of motion for a particle starting from rest under a constant electric force is given by $h = \frac{1}{2} a t^2$,where $a = \frac{qE}{m}$.Substituting $a$,we get $h = \frac{1}{2} \left( \frac{eE}{m} \right) t^2$.Therefore,the time of fall is $t = \sqrt{\frac{2hm}{eE}}$.Since $h$,$e$,and $E$ are constant for both particles,we have $t \propto \sqrt{m}$.Because the mass of an electron $(m_e \approx 9.1 \times 10^{-31} \text{ kg})$ is much smaller than the mass of a proton $(m_p \approx 1.67 \times 10^{-27} \text{ kg})$,the time taken by the electron will be smaller than the time taken by the proton.

Class 12 Physics Electric Charges and Fields Motion of Charge particle in Electric filed

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An electron falls from rest through a vertical distance $h$ in a uniform and vertically upward directed electric field $E$. The direction of the electric field is now reversed,keeping its magnitude the same. $A$ proton is allowed to fall from rest in it through the same vertical distance $h$. The time of fall of the electron,in comparison to the time of fall of the proton,is:

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smaller
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$5$ times greater
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equal
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$10$ times greater

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Electric Charges and Fields

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Motion of Charge particle in Electric filed

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$A$ stream of positively charged particles having $\frac{q}{m} = 2 \times 10^{11} \text{ C/kg}$ and velocity $\overrightarrow{v}_0 = 3 \times 10^7 \hat{i} \text{ m/s}$ is deflected by an electric field $1.8 \hat{j} \text{ kV/m}$. The electric field exists in a region of $10 \text{ cm}$ along the $x$-direction. Due to the electric field,the deflection of the charged particles in the $y$-direction is $........... \text{ mm}$.

MediumJEE MAIN 2023

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An oil drop having a mass $4.8 \times 10^{-13} \,kg$ and charge $2.4 \times 10^{-18} \,C$ stands still between two charged horizontal plates separated by a distance of $1 \,cm$. If now the polarity of the plates is changed,the instantaneous acceleration of the drop is: $(g = 10 \,m/s^2)$ (in $\,m/s^2$)

DifficultAP EAMCET 2006

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The potential difference between two metal plates is $800 \, V$ and they are separated by a horizontal distance of $0.02 \, m$. $A$ particle of mass $1.96 \times 10^{-15} \, kg$ is held in equilibrium between the plates. If $e$ is the elementary charge,then the charge on the particle is .......

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Charge $Q$ is given a displacement $\vec{r} = a\hat{i} + b\hat{j}$ in an electric field $\vec{E} = E_1\hat{i} + E_2\hat{j}$. The work done is

Easy

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$A$ charge $q_2$ of mass $m$ revolves around a stationary charge $q_1$ in a circular orbit of radius $r$. The orbital periodic time of $q_2$ would be . . . . . . .

EasyGUJCET 2011

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The potential difference between two metal plates is $800 \, V$ and they are separated by a horizontal distance of $0.02 \, m$. $A$ particle of mass $1.96 \times 10^{-15} \, kg$ is held in equilibrium between the plates. If $e$ is the elementary charge,then the charge on the particle is .......

Charge $Q$ is given a displacement $\vec{r} = a\hat{i} + b\hat{j}$ in an electric field $\vec{E} = E_1\hat{i} + E_2\hat{j}$. The work done is

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