An electron (charge q C) enters a magnetic fi | vedclass

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Question

(D) The magnetic force $\overrightarrow{F}$ on a charged particle moving in a magnetic field is given by the Lorentz force formula: $\overrightarrow{F

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Zero

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(D) The magnetic force $\overrightarrow{F}$ on a charged particle moving in a magnetic field is given by the Lorentz force formula: $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.This can be expressed in magnitude as $F = qvB \sin(	heta)$,where $	heta$ is the angle between the velocity vector $\overrightarrow{v}$ and the magnetic field vector $\overrightarrow{B}$.In this problem,the electron enters the magnetic field in the same direction as the field,which means the angle $	heta = 0^\circ$.Since $\sin(0^\circ) = 0$,the force $F = qvB \sin(0^\circ) = 0$.Therefore,the force on the electron is zero.

An electron (charge $q$ $C$) enters a magnetic field of $B$ $Wb/m^2$ with a velocity of $v$ $m/s$ in the same direction as that of the field. The force on the electron is:

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