Given below are two statements

Statement $I$ : The electric force changes the speed of the charged particle and hence changes its kinetic energy: whereas the magnetic force does not change the kinetic energy of the charged particle

Statement $II$ : The electric force accelerates the positively charged particle perpendicular to the direction of electric field. The magnetic force accelerates the moving charged particle along the direction of magnetic field. In the light of the above statements, choose the most appropriate answer from the options given below

  • [JEE MAIN 2022]
  • A

    Both Statement $I$ and Statement $II$ are correct

  • B

    Both Statement $I$ and Statement $II$ are incorrect

  • C

    Statement $I$ is correct but Statement $II$ is incorrect

  • D

    Statement $I$ is incorrect but Statement $II$ is correct

Similar Questions

When a charged particle enters a uniform magnetic field its kinetic energy

In a certain region static electric and magnetic fields exist. The magnetic field is given by $\vec B = {B_0}\left( {\hat i + 2\hat j - 4\hat k} \right)$. If a test charge moving with a velocity $\vec v = {v_0}\left( {3\hat i - \hat j + 2\hat k} \right)$ experiences no force in that region, then the electric field in the region, in $SI\, units$, is

  • [JEE MAIN 2017]

A proton and a deutron ( $\mathrm{q}=+\mathrm{e}, m=2.0 \mathrm{u})$ having same kinetic energies enter a region of uniform magnetic field $\vec{B}$, moving perpendicular to $\vec{B}$. The ratio of the radius $r_d$ of deutron path to the radius $r_p$ of the proton path is:

  • [JEE MAIN 2024]

The time period of a charged particle undergoing a circular motion in a uniform magnetic field is independent of its

  • [AIEEE 2002]

An electron gun is placed inside a long solenoid of radius $\mathrm{R}$ on its axis. The solenoid has $\mathrm{n}$ turns/length and carries a current $I$. The electron gun shoots an electron along the radius of the solenoid with speed $v$. If the electron does not hit the surface of the solenoid, maximum possible value of ${v}$ is (all symbols have their standard meaning)

  • [JEE MAIN 2020]