Two charged particle $A$ and $B$ each of charge $+e$ and masses $12$ $amu$ and $13$ $amu$ respectively follow a circular trajectory in chamber $X$ after the velocity selector as shown in the figure. Both particles enter the velocity selector with speed $1.5 \times 10^6 \,ms^{-1}.$ A uniform magnetic field of strength $1.0$ $T$ is maintained within the chamber $X$ and in the velocity selector.
Electric field across the conducting plate of the velocity selector is $- 10^6\, NC^{-1} \hat i$ .
Electric field across the conducting plate of the velocity selector is $10^6 \,NC^{-1} \hat i$ .
The ratio $r_A$/ $r_B$ of the radii of the circular paths for the two particles is $12/13.$
The ratio $r_A$ $/r_B$ of the radii of the circular paths for the two particles is $13/12$ .
A proton is projected with a velocity $10^7\, m/s$, at right angles to a uniform magnetic field of induction $100\, mT$. The time (in second) taken by the proton to traverse $90^o$ arc is $(m_p = 1.65\times10^{-27}\, kg$ and $q_p = 1.6\times10^{-19}\, C)$
The time period of a charged particle undergoing a circular motion in a uniform magnetic field is independent of its
The direction of magnetic force on the electron as shown in the diagram is along
Two charged particles of mass $m$ and charge $q$ each are projected from origin simultaneously with same speed $V$ in transverse magnetic field. If ${\vec r_1}$ and ${\vec r_2}$ are the position vectors of particles (with respect to origin) at $t = \frac{{\pi m}}{{qB}}$ then the value of ${\vec r_1}.{\vec r_2}$ at that time is
A proton carrying $1\, Me V$ kinetic energy is moving in a circular path of radius $R$ in uniform magnetic field. What should be the energy of an $\alpha -$ particle to describe a circle of same radius in the same field ?........$MeV$