Difficult
An athlete is given $100 \ g$ of glucose $(C_6H_{12}O_6)$ for energy. This is equivalent to $1800 \ kJ$ of energy. The $50 \ \%$ of this energy gained is utilized by the athlete for sports activities at the event. In order to avoid storage of energy,the weight of extra water he would need to perspire is $......... \ g$ (Nearest integer).
Assume that there is no other way of consuming stored energy. Given: The enthalpy of evaporation of water is $45 \ kJ \ mol^{-1}$.
Molar mass of $C, H$ and $O$ are $12, 1$ and $16 \ g \ mol^{-1}$.
Assume that there is no other way of consuming stored energy. Given: The enthalpy of evaporation of water is $45 \ kJ \ mol^{-1}$.
Molar mass of $C, H$ and $O$ are $12, 1$ and $16 \ g \ mol^{-1}$.
- A$180$
- B$360$
- C$90$
- D$45$
Explore More
Similar Questions
Match the following:
Column-$I$
Column-$II$
$A$. $5.6 \ L$ of $SO_{2(g)}$ at $STP$
$I$. $32 \ g$
$B$. $1.2 \times 10^{24}$ atoms of oxygen
$II$. $66 \ g$
$C$. $33.6 \ L$ of $CO_{2(g)}$ at $STP$
$III$. $42 \ g$
$D$. $1.5 \ g$-molecule of $N_2$
$IV$. $16 \ g$
The correct match is:
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. $5.6 \ L$ of $SO_{2(g)}$ at $STP$ | $I$. $32 \ g$ |
| $B$. $1.2 \times 10^{24}$ atoms of oxygen | $II$. $66 \ g$ |
| $C$. $33.6 \ L$ of $CO_{2(g)}$ at $STP$ | $III$. $42 \ g$ |
| $D$. $1.5 \ g$-molecule of $N_2$ | $IV$. $16 \ g$ |
The correct match is:
Medium
View Solution$25 \ mL$ of $0.1 \ N \ NaOH$ solution neutralises $12.5 \ mL$ of $HCl$ solution. The amount of water needed to convert $500 \ mL$ of such $HCl$ solution to $0.1 \ N$ is (in $mL$)
When $100 \ mL$ of $1 \ M \ NaOH$ solution and $10 \ mL$ of $10 \ N \ H_2SO_4$ solution are mixed together,the resulting solution will be
Medium
View SolutionCalculate the molarity of each of the following solutions: $(a)$ $30 \, g$ of $Co(NO_3)_2 \cdot 6H_2O$ in $4.3 \, L$ of solution $(b)$ $30 \, mL$ of $0.5 \, M \, H_2SO_4$ diluted to $500 \, mL$.
Difficult
View SolutionThe normality of $H_{2}SO_{4}$ in the solution obtained on mixing $100 \ mL$ of $0.1 \ M \ H_{2}SO_{4}$ with $50 \ mL$ of $0.1 \ M \ NaOH$ is $\times 10^{-1} \ N$. (Nearest Integer)
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo