Match the following:
Column-$I$ Column-$II$
$A$. $5.6 \ L$ of $SO_{2(g)}$ at $STP$ $I$. $32 \ g$
$B$. $1.2 \times 10^{24}$ atoms of oxygen $II$. $66 \ g$
$C$. $33.6 \ L$ of $CO_{2(g)}$ at $STP$ $III$. $42 \ g$
$D$. $1.5 \ g$-molecule of $N_2$ $IV$. $16 \ g$

The correct match is:

  • A
    $A-I, B-III, C-II, D-IV$
  • B
    $A-IV, B-I, C-II, D-III$
  • C
    $A-II, B-III, C-IV, D-I$
  • D
    $A-IV, B-II, C-III, D-I$

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$200 \ mL$ of a mixture of $50\% \ H_2$,$40\% \ CH_4$ and $10\% \ CO_2$ is exploded with excess of oxygen in an eudiometry tube. The resultant mixture is cooled to room temperature and is passed through $aq. KOH$. Find volume contraction after passing through $KOH$ ................. $mL$

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$10 \ mL$ of $2 \ M$ $NaOH$ solution is added to $20 \ mL$ of $1 \ M$ $HCl$ solution kept in a beaker. Now,$10 \ mL$ of this mixture is poured into a volumetric flask of $100 \ mL$ containing $2 \ moles$ of $HCl$ and made the volume up to the mark with distilled water. The solution in this flask is $:$

Substance $A_2B_{(g)}$ can undergo decomposition to form two sets of products. If the molar ratio of $A_{2(g)}$ to $A_{(g)}$ is $5 : 3$ in a set of product gases,then the energy involved in the decomposition of $1 \, \text{mole}$ of $A_2B_{(g)}$ is:
$A_2B_{(g)} \to A_{2(g)} + B_{(g)}; \Delta H^o = 40 \, \text{kJ/mol}$
$A_2B_{(g)} \to A_{(g)} + AB_{(g)}; \Delta H^o = 50 \, \text{kJ/mol}$

When a standard solution of $NaOH$ is left in air for a few hours,

Match the following columns:
Column - $A$ Column - $B$
$(A)$ $88 \ g$ of $CO_2$ $(1)$ $0.2 \ mol$
$(B)$ $6.022 \times 10^{23}$ molecules of water $(2)$ $2 \ mol$
$(C)$ $5.6 \ L$ of $O_2$ at $STP$ $(3)$ $1 \ mol$
$(D)$ $96 \ g$ of $O_2$ $(4)$ $6.022 \times 10^{23}$ molecules
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