$25 \ mL$ of $0.1 \ N \ NaOH$ solution neutralises $12.5 \ mL$ of $HCl$ solution. The amount of water needed to convert $500 \ mL$ of such $HCl$ solution to $0.1 \ N$ is (in $mL$)

  • A
    $555$
  • B
    $500$
  • C
    $50$
  • D
    $55.5$

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Similar Questions

Identify the type of reaction for the following chemical equation:
$CuSO_4 + 2NaOH (excess) \longrightarrow Cu(OH)_2 \downarrow + Na_2SO_4$

Select the correct option based on the given figure. Symbol $T$ indicates a true statement and $F$ indicates a false statement.
Solution $P = 8 \, N$ $H_2SO_{4(aq)}$ and Solution $Q = 8 \, N$ $HNO_{3(aq)}$.
$(1)$ The number of moles of solute in solution $P$ and solution $Q$ are equal.
$(2)$ The number of gram-equivalents of solute in solution $P$ and solution $Q$ are equal.
$(3)$ The mole fraction of solvent in solution $P$ and solution $Q$ are equal.
$(4)$ The concentration of $H^+_{(aq)}$ in solution $P$ and solution $Q$ are equal.

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For the reaction: $N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$,$\Delta H = -24 \ \text{kcal}$ at $427 \ ^\circ\text{C}$ and $200 \ \text{atm}$. Calculate the magnitude of the internal energy change ($\Delta U$ in $\text{kcal}$),if $168 \ \text{g}$ of $N_2$ gas and $30 \ \text{g}$ of $H_2$ gas are allowed to react completely ($100\%$ reaction yield) to form $NH_3$ gas at $427 \ ^\circ\text{C}$ and $200 \ \text{atm}$.

An aqueous solution of $6.3 \ g$ oxalic acid dihydrate is made up to $250 \ mL$. The volume of $0.1 \ N \ NaOH$ required to completely neutralize $10 \ mL$ of this solution is $...... \ mL$.

In which of the following reactions is no gas evolved on the product side? (Temperature is maintained below the boiling point of liquids formed)

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