An army vehicle of mass 1000, kg is moving wi | vedclass

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(C) Given:Mass of the vehicle,$m = 1000\, kg$Initial velocity,$u = 10\, m/s$Forward force,$F_{forward} = 1000\, N$Retarding force,$F_{friction} = 500\

Vedclass · Accepted Answer

$15$

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(C) Given:Mass of the vehicle,$m = 1000\, kg$Initial velocity,$u = 10\, m/s$Forward force,$F_{forward} = 1000\, N$Retarding force,$F_{friction} = 500\, N$Time,$t = 10\, s$Net force acting on the vehicle,$F_{net} = F_{forward} - F_{friction} = 1000 - 500 = 500\, N$According to Newton's second law,acceleration $a = \frac{F_{net}}{m} = \frac{500}{1000} = 0.5\, m/s^2$Using the first equation of motion,$v = u + at$$v = 10 + (0.5 	imes 10)$$v = 10 + 5 = 15\, m/s$Therefore,the velocity after $10\, s$ is $15\, m/s$.

An army vehicle of mass $1000\, kg$ is moving with a velocity of $10\, m/s$. It is acted upon by a forward force of $1000\, N$ due to the engine and a retarding force of $500\, N$ due to friction. What will be its velocity after $10\, s$ (in $, m/s$)?

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