(C) To convert an ammeter (or galvanometer) to measure a higher current range,a shunt resistance $S$ must be connected in parallel with it.Given:Full-

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(C) To convert an ammeter (or galvanometer) to measure a higher current range,a shunt resistance $S$ must be connected in parallel with it.Given:Full-scale current of ammeter,$I_g = 2 \, A$Resistance of ammeter,$G = 12 \, \Omega$Maximum current to be measured,$I = 5 \, A$The formula for shunt resistance is given by:$S = \frac{I_g \cdot G}{I - I_g}$Substituting the values:$S = \frac{2 \cdot 12}{5 - 2}$$S = \frac{24}{3} = 8 \, \Omega$Therefore,a resistance of $8 \, \Omega$ must be connected in parallel.

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Medium

An ammeter gives full-scale deflection when a current of $2 \, A$ flows through it. The resistance of the ammeter is $12 \, \Omega$. If the same ammeter is to be used for measuring a maximum current of $5 \, A$,then the ammeter must be connected with a resistance of:

A
$8 \, \Omega$ in series
B
$18 \, \Omega$ in series
C
$8 \, \Omega$ in parallel
D
$18 \, \Omega$ in parallel

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Class 12 Questions

Class 12

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Moving Charges and Magnetism

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The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

An ammeter with internal resistance $90\,\Omega$ reads $1.85\,A$ when connected in a circuit containing a battery and two resistors $700\,\Omega$ and $410\,\Omega$ in series. The actual current in the circuit (without the ammeter) will be:

Easy

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What is the value of shunt resistance required to convert a galvanometer of resistance $ 100 \Omega $ into an ammeter of range $ 1 \text{ A} $? Given: Full scale deflection of the galvanometer is $ 5 \text{ mA} $.

MediumKCET 2014

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An ammeter reads up to $1\, A$. Its internal resistance is $0.81\, \Omega$. To increase the range to $10\, A$,the value of the required shunt is ............ $\Omega$.

MediumAIEEE 2003

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When a shunt resistance of $4r$ is connected to a galvanometer,it becomes an ammeter that can measure $0.03 \, A$. When a shunt resistance of $r$ is connected to the same galvanometer,it becomes an ammeter that can measure $0.06 \, A$. What is the current capacity $(i_g)$ of the galvanometer in $A$?

Difficult

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$A$ certain current passing through a galvanometer produces a deflection of $100$ divisions. When a shunt of $1 \ \Omega$ is connected, the deflection reduces to $1$ division. The galvanometer resistance is: (in $\Omega$)

EasyKCET 2008

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An ammeter gives full-scale deflection when a current of $2 \, A$ flows through it. The resistance of the ammeter is $12 \, \Omega$. If the same ammeter is to be used for measuring a maximum current of $5 \, A$,then the ammeter must be connected with a resistance of:

Similar Questions

An ammeter with internal resistance $90\,\Omega$ reads $1.85\,A$ when connected in a circuit containing a battery and two resistors $700\,\Omega$ and $410\,\Omega$ in series. The actual current in the circuit (without the ammeter) will be:

What is the value of shunt resistance required to convert a galvanometer of resistance $ 100 \Omega $ into an ammeter of range $ 1 \text{ A} $? Given: Full scale deflection of the galvanometer is $ 5 \text{ mA} $.

An ammeter reads up to $1\, A$. Its internal resistance is $0.81\, \Omega$. To increase the range to $10\, A$,the value of the required shunt is ............ $\Omega$.

$A$ certain current passing through a galvanometer produces a deflection of $100$ divisions. When a shunt of $1 \ \Omega$ is connected, the deflection reduces to $1$ division. The galvanometer resistance is: (in $\Omega$)

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