A certain current passing through a galvanome | vedclass

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(B) Let the initial current be $I$ and the galvanometer resistance be $G$. The deflection is proportional to the current, so $I = k 	imes 100$, where

Vedclass · Accepted Answer

$99$

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(B) Let the initial current be $I$ and the galvanometer resistance be $G$. The deflection is proportional to the current, so $I = k 	imes 100$, where $k$ is a constant.When a shunt $S = 1 \ \Omega$ is connected in parallel, the new current through the galvanometer $I_g$ is given by the current divider rule: $I_g = I \left( \frac{S}{S+G} ight)$.The new deflection is $1$ division, so $I_g = k 	imes 1$.Substituting the values: $k = (k 	imes 100) \left( \frac{1}{1+G} ight)$.Dividing both sides by $k$: $1 = \frac{100}{1+G}$.$1+G = 100$.$G = 99 \ \Omega$.

$A$ certain current passing through a galvanometer produces a deflection of $100$ divisions. When a shunt of $1 \ \Omega$ is connected, the deflection reduces to $1$ division. The galvanometer resistance is: (in $\Omega$)

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