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(A) The given alternating voltage is $E = 20 \sin 300t$.The average value of a sinusoidal alternating voltage over one complete cycle is defined as th

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$0$

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(A) The given alternating voltage is $E = 20 \sin 300t$.The average value of a sinusoidal alternating voltage over one complete cycle is defined as the integral of the voltage over the time period $T$ divided by the time period $T$.Mathematically,$E_{avg} = \frac{1}{T} \int_{0}^{T} E_0 \sin(\omega t) dt$.Since the sine function is symmetric about the time axis,the area under the positive half-cycle is equal to the area under the negative half-cycle.Therefore,the positive and negative values cancel each other out,resulting in an average value of $0$ over one complete cycle.

$(A) \ x_0 \sin \omega t$	$(i) \ x_0$
$(B) \ x_0 \sin \omega t \cos \omega t$	$(ii) \ \frac{x_0}{\sqrt{2}}$
$(C) \ x_0 \sin \omega t + x_0 \cos \omega t$	$(iii) \ \frac{x_0}{2 \sqrt{2}}$

An alternating voltage is represented as $E = 20 \sin 300t$. The average value of voltage over one cycle will be ....... $V$.

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