An alternating e.m.f. is given by $e = e_{0} \sin(\omega t)$. In what time will the e.m.f. reach half its maximum value,if $e$ starts from zero? ($T$ = Time period)

If an alternating voltage is represented as $E = 141 \sin(628 t)$,then the rms value of the voltage and the frequency are respectively:

In an $ac$ circuit,the instantaneous voltage $e(t)$ and current $i(t)$ are given by $e(t) = 5[\cos \omega t + \sqrt{3} \sin \omega t] \ V$ and $i(t) = 5[\sin(\omega t + \frac{\pi}{4})] \ A$. Determine the phase relationship between voltage and current.

In Karnataka,the normal domestic power supply $AC$ is $220 \text{ V}, 50 \text{ Hz}$. Here $220 \text{ V}$ and $50 \text{ Hz}$ refer to:

The mean and $rms$ value of an alternating voltage for a half cycle,as shown in the figure,are respectively:

The instantaneous value of current in an $A.C.$ circuit is $I = 3 \sin \left(50 \pi t + \frac{\pi}{4}\right) \text{ A}$. The current will be maximum for the first time at