In Rutherford's experiment, number of par | vedclass

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Question

(b)

$N(	heta) \propto \frac{Z^2}{\sin ^4\left(\frac{	heta}{2}ight) E^2}$

$	ext { or } N (	heta) \propto \frac{1}{\sin ^4\left(\frac{	heta

Vedclass · Accepted Answer

$4 x$

Vedclass · Answer

(b)

$N(	heta) \propto \frac{Z^2}{\sin ^4\left(\frac{	heta}{2}ight) E^2}$

$	ext { or } N (	heta) \propto \frac{1}{\sin ^4\left(\frac{	heta}{2}ight)}$

$	heta=60^{\circ}$ and $90^{\circ}$

$	herefore \frac{N(90)}{N(60)} \propto \frac{\sin ^4 30}{\sin ^4 45}$

$N\left(90^{\circ}ight)=x$

$N\left(60^{\circ}ight)=4 x$

In Rutherford's experiment, number of particles scattered at $90^{\circ}$ angle are $x$ per second. Number particles scattered per second at angle $60^{\circ}$ is

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