An alkene $'A'$ contains three $C-C$,eight $C-H$ $\sigma$ bonds and one $C-C$ $\pi$ bond. $'A'$ on ozonolysis gives two moles of an aldehyde of molar mass $44 \ u$. Write the $IUPAC$ name of $'A'$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) As per the given information,$'A'$ on ozonolysis gives two moles of an aldehyde of molar mass $44 \ u$. The formation of two moles of an aldehyde indicates the presence of identical structural units on both sides of the double bond. The molar mass of the aldehyde is $44 \ u$,which corresponds to ethanal $(CH_3CHO)$.
Since two moles of ethanal are produced,the alkene must be $CH_3-CH=CH-CH_3$ (but-$2$-ene).
Verification of bonds in but-$2$-ene $(C_4H_8)$:
- $C-C$ $\sigma$ bonds: $3$ $(C_1-C_2, C_2-C_3, C_3-C_4)$
- $C-H$ $\sigma$ bonds: $8$
- $C-C$ $\pi$ bond: $1$
Ozonolysis reaction:
$CH_3-CH=CH-CH_3 + O_3 \to \text{ozonide} \xrightarrow{Zn/H_2O} 2CH_3CHO$
The $IUPAC$ name of $'A'$ is but-$2$-ene.

Explore More

Similar Questions

Reactivity order of alkenes towards electrophilic addition reaction:
$I: CH_2=CH_2$
$II: CH_3-CH=CH_2$
$III: CH_3-C(CH_3)=CH_2$
$IV: CH_2=CH-Cl$

Difficult
View Solution

An alkene gives two moles of $HCHO$,one mole of $CO_2$,and one mole of $CH_3COCHO$ on ozonolysis. What is its structure?

An alkene $X$ $(C_6H_{12})$ on ozonolysis gives acetaldehyde and ethyl methyl ketone. What is the product formed when $X$ reacts with $HBr$?

$X$ is

Ozonolysis of which one of the following will give two molecules of acetaldehyde?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo