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(C) The reaction of allylbenzene $(Ph-CH_2-CH=CH_2)$ with $HBr$ in the presence of peroxide $(R_2O_2)$ follows the anti-Markovnikov addition rule (Kha

Vedclass · Accepted Answer

$Ph-CH_2-CH_2-CH_2-Br$

Vedclass · Answer

(C) The reaction of allylbenzene $(Ph-CH_2-CH=CH_2)$ with $HBr$ in the presence of peroxide $(R_2O_2)$ follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).According to this rule,the bromine atom attaches to the carbon atom of the double bond that has more hydrogen atoms.In the reactant $Ph-CH_2-CH=CH_2$,the terminal carbon $(CH_2)$ has two hydrogen atoms,while the internal carbon $(CH)$ has one hydrogen atom.Therefore,the $Br$ atom adds to the terminal $CH_2$ group,and the $H$ atom adds to the $CH$ group.The product formed is $Ph-CH_2-CH_2-CH_2-Br$ ($1$-phenyl$-3-$bromopropane).Thus,the correct option is $C$.

$X$ is

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