An $\alpha$-particle of energy $5 \text{ MeV}$ is scattered through $180^{\circ}$ by a gold nucleus. The distance of closest approach is of the order of:

  • A
    $10^{-10} \text{ cm}$
  • B
    $10^{-12} \text{ cm}$
  • C
    $10^{-14} \text{ cm}$
  • D
    $10^{-16} \text{ cm}$

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