Among the following configurations,the element which has the highest electron affinity is

  • A
    $[Ne] \, 3s^2, \, 3p^1$
  • B
    $[Ne] \, 3s^2, \, 3p^5$
  • C
    $[Ne] \, 3s^2, \, 3p^4$
  • D
    $[Ne] \, 3s^2, \, 3p^6, \, 3d^5, \, 4s^1$

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Similar Questions

Evaluate the following statements regarding electron affinity $(EA)$:
$A$. Carbon is greater than fluorine
$B$. Sulphur is lesser than fluorine
$C$. Iodine is higher than bromine
$D$. Chlorine is greater than sulphur
Select the correct sequence of truth values ($T$ for true,$F$ for false):

The formation of the oxide ion,$O^{2-}_{(g)}$,from oxygen atom requires first an exothermic and then an endothermic step as shown below:
$O_{(g)} + e^- \to O^{-}_{(g)} ; \Delta_f H^{\Theta} = -141 \ kJ \ mol^{-1}$
$O^{-}_{(g)} + e^- \to O^{2-}_{(g)} ; \Delta_f H^{\Theta} = +780 \ kJ \ mol^{-1}$
Thus,the process of formation of $O^{2-}$ in gas phase is unfavourable even though $O^{2-}$ is isoelectronic with neon. It is due to the fact that,

Explain the periodicity of electron gain enthalpy of elements in the periodic table.

Which of the following has the maximum electron gain enthalpy?

Match the following elements in List-$I$ with their respective electron gain enthalpy values in List-$II$:
List-$I$ (Element)List-$II$ (Electron gain enthalpy in $kJ \ mol^{-1}$)
$(A)$ $F$$(I)$ $-141$
$(B)$ $Cl$$(II)$ $-328$
$(C)$ $O$$(III)$ $-200$
$(D)$ $S$$(IV)$ $-349$

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