The number of geometric isomers possible for the complex $[CoL_2 Cl_2]^{-}$ where $L = H_2NCH_2CH_2O^{-}$ is

Given below are two statements:
Statement-$I$ : The number of paramagnetic species among $[CoF_6]^{3-}$,$[TiF_6]^{3-}$,$V_2O_5$ and $[Fe(CN)_6]^{3-}$ is $3$.
Statement-$II$ : $K_4[Fe(CN)_6] < K_3[Fe(CN)_6] < [Fe(H_2O)_6]SO_4 \cdot H_2O < [Fe(H_2O)_6]Cl_3$ is the correct order in terms of number of unpaired electron$(s)$ in the complexes.
In the light of the above statements,choose the correct answer from the options given below.

Consider the complex ions,$trans-[Co(en)_2Cl_2]^+$ $(A)$ and $cis-[Co(en)_2Cl_2]^+$ $(B)$. The correct statement regarding them is :

$X$ is the number of geometrical isomers exhibited by $[Pt(NH_3)(H_2O)BrCl]$.
$Y$ is the number of optically inactive isomer$(s)$ exhibited by $[CrCl_2(ox)_2]^{3-}$.
$Z$ is the number of geometrical isomers exhibited by $[Co(NH_3)_3(NO_2)_3]$.
The value of $X+Y+Z$ is . . . . . . .

Identify the homoleptic complex(es) that is/are low spin.
$(A) \ [Fe(CN)_5NO]^{2-}$
$(B) \ [CoF_6]^{3-}$
$(C) \ [Fe(CN)_6]^{4-}$
$(D) \ [Co(NH_3)_6]^{3+}$
$(E) \ [Cr(H_2O)_6]^{2+}$
Choose the correct answer from the options given below:

The correct increasing order of spin-only magnetic moment values of the complex ions $[MnBr_{4}]^{2-}$ $(A)$, $[Cu(H_{2}O)_{6}]^{2+}$ $(B)$, $[Ni(CN)_{4}]^{2-}$ $(C)$ and $[Ni(H_{2}O)_{6}]^{2+}$ $(D)$ is: