Although Zr belongs to the 4d transition seri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) . The difficulty in separating $Zr$ and $Hf$ arises because they possess almost identical atomic and ionic radii.
This phenomenon is a direct con

Vedclass · Accepted Answer

Due to similar atomic sizes caused by lanthanoid contraction.

Vedclass · Answer

(A) . The difficulty in separating $Zr$ and $Hf$ arises because they possess almost identical atomic and ionic radii.
This phenomenon is a direct consequence of the lanthanoid contraction.
As we move from the $4d$ to the $5d$ series,the filling of $4f$ orbitals occurs before the $5d$ orbitals.
The $4f$ electrons provide poor shielding of the nuclear charge,which leads to an increase in the effective nuclear charge.
This causes the atomic radii of $5d$ elements (like $Hf$) to be very similar to those of the corresponding $4d$ elements (like $Zr$).

Although $Zr$ belongs to the $4d$ transition series and $Hf$ belongs to the $5d$ transition series,it is quite difficult to separate them. Why?

Similar Questions

Which of the following metal ions will have the maximum number of unpaired electrons?

Which of the following triads has approximately equal size?

What is the general electronic configuration of the outermost shell of $f$-block elements?

The magnetic moment of a metal ion of the first transition series is $2.83 \ BM$. Therefore,it will have how many unpaired electrons?

Vedclass Test Series

Exam Paper Generator

Online Exam Module