The $3d$ metal ions form coloured compounds because the energy corresponding to the following lies in the visible range of the electromagnetic spectrum:

  • A
    Free energy change of complex formation by $3d$ metal ions
  • B
    $d-d$ transitions of $3d$ electrons
  • C
    Heat of hydration of $3d$ metal ions
  • D
    Ionisation energy of $3d$ metal ions

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Similar Questions

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

Consider the metal complexes $[Ni(en)_3]^{2+}$ $(A)$, $[NiCl_4]^{2-}$ $(B)$ and $[Ni(NH_3)_6]^{2+}$ $(C)$. Choose the $\text{CORRECT}$ option by considering the number of unpaired electrons present in $(A)$, $(B)$ and $(C)$ respectively and the order of frequency of absorption.

Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?

Low spin complex of $d^6$ cation in an octahedral field will have the following energy:
($\Delta_o =$ crystal field splitting energy in an octahedral field,$P =$ Electron pairing energy)

The number of unpaired $d$-electrons in $[Co(H_2O)_6]^{3+}$ is $\qquad$

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