Albert invested an amount of x rupees in a fi | vedclass

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(B) The amount after the first year is $x 	imes (1 + \frac{10}{100}) = x 	imes \frac{110}{100}$.After the second year,the amount becomes $(x 	imes

Vedclass · Accepted Answer

$16000$

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(B) The amount after the first year is $x 	imes (1 + \frac{10}{100}) = x 	imes \frac{110}{100}$.After the second year,the amount becomes $(x 	imes \frac{110}{100}) 	imes (1 + \frac{15}{100}) = x 	imes \frac{110}{100} 	imes \frac{115}{100}$.Given that the final amount is ₹ $20,240$,we have:$x 	imes \frac{110}{100} 	imes \frac{115}{100} = 20240$.$x 	imes 1.1 	imes 1.15 = 20240$.$x 	imes 1.265 = 20240$.$x = \frac{20240}{1.265} = 16000$.Therefore,the principal amount $x$ is ₹ $16000$.

Albert invested an amount of $x$ rupees in a fixed deposit scheme offering $10 \%$ per annum for the $1^{\text{st}}$ year and $15 \%$ per annum for the $2^{\text{nd}}$ year and received an amount of ₹ $20,240$ after two years. What is $x$ (in ₹)?

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