Gaurav borrowed Rs. 800 at 6 % and Naresh bor | vedclass

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(D) Let the time be $T$ years.The amount (debt) is calculated as $A = P + SI = P + \frac{P 	imes R 	imes T}{100}$.For Gaurav: $P_1 = 800, R_1 = 6 \%

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$16 \frac{2}{3} 	ext{ years}$

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(D) Let the time be $T$ years.The amount (debt) is calculated as $A = P + SI = P + \frac{P 	imes R 	imes T}{100}$.For Gaurav: $P_1 = 800, R_1 = 6 \%$.Debt $A_1 = 800 + \frac{800 	imes 6 	imes T}{100} = 800 + 48T$.For Naresh: $P_2 = 600, R_2 = 10 \%$.Debt $A_2 = 600 + \frac{600 	imes 10 	imes T}{100} = 600 + 60T$.According to the question,the debts are equal:$800 + 48T = 600 + 60T$.Rearranging the terms:$800 - 600 = 60T - 48T$.$200 = 12T$.Solving for $T$:$T = \frac{200}{12} = \frac{50}{3} = 16 \frac{2}{3} 	ext{ years}$.

Gaurav borrowed $Rs. 800$ at $6 \%$ and Naresh borrowed $Rs. 600$ at $10 \%$. After how much time will they both have equal debts?

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