Acetaldehyde on treatment with dil. NaOH foll | vedclass

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Question

(C) Acetaldehyde $(CH_3CHO)$ contains $\alpha$-hydrogens and undergoes an aldol condensation reaction in the presence of dilute $NaOH$.Step $1$: Two m

Vedclass · Accepted Answer

$CH_3-CH=CHCHO$

Vedclass · Answer

(C) Acetaldehyde $(CH_3CHO)$ contains $\alpha$-hydrogens and undergoes an aldol condensation reaction in the presence of dilute $NaOH$.Step $1$: Two molecules of acetaldehyde react to form $3$-hydroxybutanal (aldol).$2CH_3CHO \xrightarrow{dil. NaOH} CH_3-CH(OH)-CH_2-CHO$Step $2$: Upon heating,the aldol undergoes dehydration to form an $\alpha,\beta$-unsaturated aldehyde,which is but-$2$-enal.$CH_3-CH(OH)-CH_2-CHO \xrightarrow{\Delta} CH_3-CH=CH-CHO + H_2O$Thus,the final product is $CH_3-CH=CHCHO$.

Acetaldehyde on treatment with dil. $NaOH$ followed by heating gives:

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