Correct order for nucleophilic addition reaction :
$(1)$ $C_{6}H_{5}COC_{6}H_{5}$
$(2)$ $C_{6}H_{5}CHO$
$(3)$ $p-CH_{3}C_{6}H_{4}CHO$
$(4)$ $p-CH_{3}OC_{6}H_{4}CHO$

The option$(s)$ with the correct sequence of reagents for the conversion of $P$ to $Q$ is(are):
$(A)$ $i$) Lindlar's catalyst,$H_2$; $ii$) $SnCl_2 / HCl$; $iii$) $NaBH_4$; $iv$) $H_3O^{+}$
$(B)$ $i$) Lindlar's catalyst,$H_2$; $ii$) $H_3O^{+}$; $iii$) $SnCl_2 / HCl$; $iv$) $NaBH_4$
$(C)$ $i$) $NaBH_4$; $ii$) $SnCl_2 / HCl$; $iii$) $H_3O^{+}$; $iv$) Lindlar's catalyst,$H_2$
$(D)$ $i$) Lindlar's catalyst,$H_2$; $ii$) $NaBH_4$; $iii$) $SnCl_2 / HCl$; $iv$) $H_3O^{+}$

$CH_3-CO-OC_2H_5 \xrightarrow{H_2N-NH_2} X$; $CH_3-CO-C_2H_5 \xrightarrow{H_2N-NH_2} Y$. $X$ and $Y$ are:

The conversion of acetophenone into benzoic acid can be achieved by its reaction with

$A$ tertiary alcohol $H$ upon acid-catalysed dehydration gives a product $I$. Ozonolysis of $I$ leads to compounds $J$ and $K$. Compound $J$ upon reaction with $KOH$ gives benzyl alcohol and a compound $L$,whereas $K$ on reaction with $KOH$ gives only $M$.
$1.$ Compound $H$ is formed by the reaction of
$2.$ The structure of compound $I$ is
$3.$ The structures of compounds $J, K$ and $L$,respectively,are
$(A)$ $PhCOCH_3, PhCH_2 COCH_3$ and $PhCH_2 COO^{-} K^{+}$
$(B)$ $PhCHO, PhCH_2 CHO$ and $PhCOO^{-} K^{+}$
$(C)$ $PhCOCH_3, PhCH_2 CHO$ and $CH_3 COO^{-} K^{+}$
$(D)$ $PhCHO, PhCOCH_3$ and $PhCOO^{-} K^{+}$
Give the answer for questions $1, 2$ and $3.$

An organic compound $A$ on reaction with $PCC$ $(\text{Pyridinium chlorochromate})$ gives a compound $B$. $B$ on further reaction with $I_2$ and $NaOH$ forms tri-iodomethane. Identify the compound $A$.