Upon treatment with I_{2} and aqueous NaOH,wh | vedclass

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Question

(D) The iodoform test is given by compounds containing the $CH_{3}CO-$ group or compounds that can be oxidized to this group,such as secondary alcohol

Vedclass · Accepted Answer

$CH_{3} CH_{2} CH_{2} CH(OH) CH_{3}$

Vedclass · Answer

(D) The iodoform test is given by compounds containing the $CH_{3}CO-$ group or compounds that can be oxidized to this group,such as secondary alcohols with the $CH_{3}CH(OH)-$ group.Option $A$: $CH_{3} CH_{2} CH_{2} CH_{2} CHO$ is a pentanal,which does not contain the $CH_{3}CO-$ group.Option $B$: $CH_{3} CH_{2} CO CH_{2} CH_{3}$ is pentan-$3$-one,which lacks the $CH_{3}CO-$ group.Option $C$: $CH_{3} CH_{2} CH_{2} CH_{2} CH_{2} OH$ is pentan-$1$-ol,a primary alcohol that does not form the required methyl ketone upon oxidation.Option $D$: $CH_{3} CH_{2} CH_{2} CH(OH) CH_{3}$ is pentan-$2$-ol. It contains the $CH_{3}CH(OH)-$ group,which is oxidized by $I_{2}/NaOH$ to pentan-$2$-one $(CH_{3} CH_{2} CH_{2} CO CH_{3})$,a methyl ketone that subsequently undergoes the iodoform reaction to produce $CHI_{3}$ (iodoform).

Upon treatment with $I_{2}$ and aqueous $NaOH$,which of the following compounds will form iodoform?

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