A wire carrying current $I$ is tied between points $P$ and $Q$ and is in the shape of a circular arc of radius $R$ due to a uniform magnetic field $B$ (perpendicular to the plane of the paper, shown by $\times \times \times $) in the vicinity of the wire. If the wire subtends an angle $2\theta_0$ at the centre of the circle (of which it forms an arc) then the tension in the wire is
A wire carrying current $I$ is tied between points $P$ and $Q$ and is in the shape of a circular arc of radius $R$ due to a uniform magnetic field $B$ (perpendicular to the plane of the paper, shown by $\times \times \times $) in the vicinity of the wire. If the wire subtends an angle $2\theta_0$ at the centre of the circle (of which it forms an arc) then the tension in the wire is
- [JEE MAIN 2015]
- A
$\frac{{IBR}}{{2\,\sin \,{\theta _0}}}$
- B
$\frac{{IBR{\theta _0}}}{{\sin \,{\theta _0}}}$
- C
$IBR$
- D
$\frac{{IBR}}{{\,\sin \,{\theta _0}}}$
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