A wheel of a bullock cart is rolling on a lev | vedclass

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Question

(A) In the case of pure rolling motion,the velocity of any point on the rim of the wheel is the vector sum of the translational velocity of the center

Vedclass · Accepted Answer

Point $P$ moves faster than point $Q$

Vedclass · Answer

(A) In the case of pure rolling motion,the velocity of any point on the rim of the wheel is the vector sum of the translational velocity of the center of mass $(v)$ and the tangential velocity due to rotation $(v = r\omega)$.For the topmost point $P$,the translational velocity and the rotational velocity are in the same direction. Thus,the resultant velocity is $v + v = 2v$.For the lowest point $Q$,the translational velocity is in the forward direction $(v)$ and the rotational velocity is in the backward direction $(v)$. Thus,the resultant velocity is $v - v = 0$.Since the velocity of point $P$ is $2v$ and the velocity of point $Q$ is $0$,point $P$ moves faster than point $Q$.

$A$ wheel of a bullock cart is rolling on a level road as shown in the figure. If its linear speed is $v$ in the direction shown,which one of the following options is correct ($P$ and $Q$ are the highest and lowest points on the wheel,respectively)?

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