$A$ vehicle travels $4\,km$ with a speed of $3\,km/h$ and another $4\,km$ with a speed of $5\,km/h$. What is its average speed in $km/h$?

"The magnitude of average velocity is equal to average speed". This statement is not always correct and not always incorrect. Explain with an example.

$A$ car covers a distance at a speed of $60 \ km \ h^{-1}$. It returns and comes back to the original point moving at a speed of $V$. If the average speed for the round trip is $48 \ km \ h^{-1}$,then the magnitude of $V$ is (in $km \ h^{-1}$)

$A$ biker travels $\frac{1}{3}$ of the distance $L$ with speed $v_1$ and $\frac{2}{3}$ of the distance with speed $v_2$. Then the average speed is

$A$ car moves for half of its time at $80 \, km/h$ and for the rest half of the time at $40 \, km/h$. The total distance covered is $60 \, km$. What is the average speed of the car in $km/h$?

$A$ particle moves along a straight line along the $x$-axis. Its position $(x)$ versus time $(t)$ graph is shown in the figure [$x$ in meters and $t$ in seconds]. Its average speed during this motion is (in $\text{ m/s}$)