$A$ biker travels $\frac{1}{3}$ of the distance $L$ with speed $v_1$ and $\frac{2}{3}$ of the distance with speed $v_2$. Then the average speed is

  • A
    $\frac{v_1 v_2}{v_1+v_2}$
  • B
    $\frac{3 v_1 v_2}{2 v_1+v_2}$
  • C
    $\frac{3 v_1 v_2}{v_1+2 v_2}$
  • D
    $\frac{v_1+v_2}{v_1 v_2}$

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