$A$ uniform wire is bent in the form of a circle of radius $R$. $A$ current $I$ enters at $A$ and leaves at $C$ as shown in the figure. If the length $ABC$ is half of the length $ADC$,the magnetic field at the centre $O$ will be

  • A
    Zero
  • B
    $\frac{\mu_0 I}{2R}$
  • C
    $\frac{\mu_0 I}{4R}$
  • D
    $\frac{\mu_0 I}{6R}$

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