A coil having $N$ turns is wound tightly in the form of a spiral with inner and outer radii $a$ and $b$ respectively. When a current $i$ passes through the coil, the magnetic field at the centre is
$\frac{{{\mu _0}Ni}}{b}$
$\frac{{2{\mu _0}Ni}}{a}$
$\frac{{{\mu _0}Ni}}{{2\left( {b - a} \right)}}ln\frac{b}{a}$
$\frac{{{\mu _0}Ni}}{{\left( {b - a} \right)}}ln\frac{b}{a}$
Two circular loops having same radius $[ R =10\, cm ]$ and same current $\frac{7}{2} A$ are placed along same axis as shown. If distance between their centre is $10\, cm$, find net magnetic field at of point $P.$
If we double the radius of a coil keeping the current through it unchanged, then the magnetic field at any point at a large distance from the centre becomes approximately
Due to $10\, ampere$ of current flowing in a circular coil of $10\, cm$ radius, the magnetic field produced at its centre is $3.14 \times {10^{ - 3}}\,Weber/{m^2}$. The number of turns in the coil will be
The magnetic field due to a current carrying square loop of side a at a point located symmetrically at a distance of $a/2$ from its centre (as shown is)
If induction of magnetic field at a point is $B$ and energy density is $U$ then which of the following graphs is correct