A uniform rod of length L and weight W is sus | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $T_1$ be the tension in the first rope and $T_2$ be the tension in the second rope.Since the rod is in equilibrium,the sum of vertical forces

Vedclass · Accepted Answer

$\frac{2W}{3}$

Vedclass · Answer

(D) Let $T_1$ be the tension in the first rope and $T_2$ be the tension in the second rope.Since the rod is in equilibrium,the sum of vertical forces is zero:$T_1 + T_2 = W$  --- $(1)$Taking the moment of forces about the left end (point $A$):The weight $W$ acts at the center of the rod,which is at a distance $L/2$ from the left end.The second rope is attached at a distance $L - L/4 = 3L/4$ from the left end.For rotational equilibrium,the sum of torques about $A$ must be zero:$W 	imes \frac{L}{2} - T_2 	imes \frac{3L}{4} = 0$$W 	imes \frac{L}{2} = T_2 	imes \frac{3L}{4}$$T_2 = W 	imes \frac{L}{2} 	imes \frac{4}{3L}$$T_2 = \frac{2W}{3}$

$A$ uniform rod of length $L$ and weight $W$ is suspended horizontally by two vertical ropes as shown. The first rope is attached to the left end of the rod while the second rope is attached at a distance $L/4$ from the right end. The tension in the second rope is

Similar Questions

As shown in the figure,a person holds a book between their finger and thumb (the book is held at the corner). If the weight of the book is $W$,what is the torque exerted by the person on the book?

$A$ horizontal force $F$ is applied to a block as shown in the figure such that the block remains in a state of rest. Which of the following statements is true?

$A$ weightless rod is acted on by upward parallel forces of $2N$ and $4N$ at ends $A$ and $B$ respectively. The total length of the rod $AB = 3m$. To keep the rod in equilibrium,a force of $6N$ should act in the following manner:

For the system to be in equilibrium,the value of mass $m$ should be .......... $kg$.

$A$ metal bar $70 \; cm$ long and $4.00 \; kg$ in mass is supported on two knife-edges placed $10 \; cm$ from each end. $A$ $6.00 \; kg$ load is suspended at $30 \; cm$ from one end. Find the reactions at the knife-edges. (Assume the bar to be of uniform cross-section and homogeneous.)

Vedclass Test Series

Exam Paper Generator

Online Exam Module