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Question

(B) Let the speed of the bus be $v_b = v \, km/h$.Since the train is $50\%$ faster than the bus, the speed of the train is $v_t = v + 0.5v = 1.5v \, k

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(B) Let the speed of the bus be $v_b = v \, km/h$.Since the train is $50\%$ faster than the bus, the speed of the train is $v_t = v + 0.5v = 1.5v \, km/h$.The distance between point $A$ and point $B$ is $d = 75 \, km$.The time taken by the bus is $t_b = \frac{75}{v}$.The time taken by the train is $t_t = \frac{75}{1.5v} = \frac{50}{v}$.The train stops for $12.5 \, minutes$, which is $\frac{12.5}{60} = \frac{125}{600} = \frac{5}{24} \, hours$.Since both reach at the same time, the difference in travel time is equal to the stoppage time:$t_b - t_t = 	ext{stoppage time}$$\frac{75}{v} - \frac{50}{v} = \frac{5}{24}$$\frac{25}{v} = \frac{5}{24}$$v = \frac{25 	imes 24}{5} = 5 	imes 24 = 120 \, km/h$.Thus, the speed of the bus is $120 \, km/h$.

$A$ train can travel $50\%$ faster than a bus. Both start from point $A$ at the same time and reach point $B$ at the same time. Point $B$ is $75 \, km$ away from point $A$. On the way, the train stops for $12.5 \, minutes$. The speed of the bus is (in $km/h$):

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