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(C) When two objects move in the same direction,their relative speed is the difference of their individual speeds.Relative speed $= (50 - 30) 	ext{ k

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) When two objects move in the same direction,their relative speed is the difference of their individual speeds.Relative speed $= (50 - 30) 	ext{ km/hr} = 20 	ext{ km/hr}$.To convert the speed from $	ext{km/hr}$ to $	ext{m/s}$,multiply by $\frac{5}{18}$:Relative speed $= 20 	imes \frac{5}{18} 	ext{ m/s} = \frac{100}{18} 	ext{ m/s}$.The faster train crosses a man in the slower train,which means the distance covered is equal to the length of the faster train.Distance $= 	ext{Relative speed} 	imes 	ext{Time}$.Length of the faster train $= \left( 20 	imes \frac{5}{18} ight) 	ext{ m/s} 	imes 18 	ext{ s} = 100 	ext{ meters}$.

Two trains are moving in the same direction at $50 \text{ km/hr}$ and $30 \text{ km/hr}$. The faster train crosses a man sitting in the slower train in $18 \text{ seconds}$. Find the length of the faster train in meters.

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