A, B and C start together from the same place | vedclass

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(D) The time taken by each person to complete one round of the circular path is calculated as $	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}}$.For

Vedclass · Accepted Answer

$24$

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(D) The time taken by each person to complete one round of the circular path is calculated as $	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}}$.For $A$: $T_A = \frac{12 \, km}{4 \, km/h} = 3 \, h$.For $B$: $T_B = \frac{12 \, km}{3 \, km/h} = 4 \, h$.For $C$: $T_C = \frac{12 \, km}{1.5 \, km/h} = \frac{12 	imes 2}{3} = 8 \, h$.To find when they will meet at the starting point,we need to calculate the Least Common Multiple $(LCM)$ of the times taken by each to complete one round.$LCM(3, 4, 8) = 24$.Therefore,they will meet together at the starting place at the end of $24 \, h$.

$A, B$ and $C$ start together from the same place to walk around a circular path of length $12 \, km$. $A$ walks at the rate of $4 \, km/h$,$B$ at $3 \, km/h$,and $C$ at $\frac{3}{2} \, km/h$. They will meet together at the starting place at the end of (in $h$):

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