A train $100 \,m$ long is moving with a velocity of $60\, km h^{-1}$. Find the time it takes to cross the bridge $1\, km$ long.
Given length' of train $=100 m$, length of bridge $=1 km =1000 m , v=60 km h ^{-1}$
Total distance to cover $100+1000=1100 m$
Therefore, time taken
$t=\frac{S}{v}=\frac{1100 \times 18}{60 \times 5}=66 s$
Two cars moving in opposite directions cover same distance $'d'$ in one hour. If the cars were moving in north$-$south direction, what will be their displacement in one hour ?
Two cars $A$ and $B$ have their displacement$-$time graph as given below. Which car has a greater velocity ?
Identify what do the graphs shown below indicate ?
A body thrown in the vertically upward direction rises upto a height $'h^{\prime}$ and comes back to the position of its start.
Calculate :
$(a)$ the total distance travelled by the body and
$(b)$ the displacement of the body. Under what condition will the magnitude of the displacement be equal to the distance travelled by an object ?
The velocity-time graph of cars $A$ and $B$ which start from the same place and move along a straight road in the same direction is shown below
Calculate :
$(a)$ the acceleration of car $B$ between $2 \,s$ and $4\, s$.
$(b)$ the time at which both the cars have the same velocity.
$(c)$ the distance travelled by the two cars $A$ and $B$ in $8\, s$
$(d)$ Which of the two cars is ahead after $8\, s$ and by how much ?