A body thrown in the vertically upward direction rises upto a height $'h^{\prime}$ and comes back to the position of its start.
Calculate :
$(a)$ the total distance travelled by the body and
$(b)$ the displacement of the body. Under what condition will the magnitude of the displacement be equal to the distance travelled by an object ?
$(a)$ Since it travels a distance $h$ upwards and $h$ downwards, therefore, total distance travelled is $h+h=2 h$
$(b)$ As the body returns to its point of throw, therefore, displacement is zero.
Magnitude of displacement can be equal to the distance travelled, if the object is moving along a straight line.
A motor car slows down from $72\, km h ^{-1}$ to $36\, km h^{-1}$ over at distance of $25\, m$. If the brakes are applied with the same force calculate $(i)$ total time in which car comes to rest $(ii)$ distance travelled by it.
Derive the equation $v^{2}-u^{2}=2 a S$ graphically.
If the displacement of a body is proportional to the square of the time elapsed, what type of motion does the body possess ?
The following table shows the positive of Renu, while she is going to her school. Draw distance$-$time graph for her motion.
Time | Distance from her home $( k m )$ |
$06: 45\, am$ | $0$ |
$07: 00 \,am$ | $8$ |
$01: 30\, pm$ | $8$ |
$01: 45\, pm$ | $0$ |
When is the acceleration $(i)$ positive $(ii)$ negative ?