The velocity-time graph of cars $A$ and $B$ which start from the same place and move along a straight road in the same direction is shown below
Calculate :
$(a)$ the acceleration of car $B$ between $2 \,s$ and $4\, s$.
$(b)$ the time at which both the cars have the same velocity.
$(c)$ the distance travelled by the two cars $A$ and $B$ in $8\, s$
$(d)$ Which of the two cars is ahead after $8\, s$ and by how much ?
$(a)$ $a=$ slope of $v-t$ graph $=\frac{40-20}{4-2}=\frac{20}{2}$
$=10 m s ^{-2}$
$(b)$ $2$ second
$(c)$ Car $A : 390 m ,$ Car $B : 320 m$
Distance $=$ Area under $v-t$ graph
Car $B$ $x=\frac{1}{2} \times 8 \times 80=320 m$
Car $A$ $x=\left(\frac{1}{2} \times 3 \times 60\right)+(60 \times 5)$
$=90+300$
$=390 m$
$(d)$ Car $B,$ $20 m$
$(a)$ Which type of motion is represented by the velocity$-$time graph shown below ?
$(b)$ Name the physical quantity which can be calculated by the area of rectangle $OABC$.
$(c)$ What does the straight line $AB$ represents ?
The branch of Physics which deals with the motion of objects while taking into consideration the cause of motion is
What can you conclude about the motion of a body depicted by the velocity$-$time graphs $(i),(i i)$ and $(i i i)$ given below
Can the distance travelled by a particle be zero when displacement is not zero ?
A cyclist driving at $36\, km h^{-1}$ stops his cycle in $2\, s$ by the application of brakes. Calculate $(i)$ retardation $(ii)$ distance covered during the application of brakes.