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(D) According to the Lens Maker's Formula,the focal length $f$ of a thin lens is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) According to the Lens Maker's Formula,the focal length $f$ of a thin lens is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.When the lens is reversed,the values of $R_1$ and $R_2$ are interchanged and their signs are also swapped,but the overall value of $\frac{1}{f}$ remains unchanged because the formula is symmetric with respect to the lens orientation.Since the focal length $f$ remains the same and the object distance $u$ is kept constant,the image distance $v$ determined by the lens formula $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$ will also remain the same in both cases.Therefore,the difference in the image position for both cases is $0$.

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