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(C) According to Ohm's law, $V = IR$, which implies $I = V/R$ or $R = V/I$.In the given $I-V$ graph, the slope of the line represents $I/V$, which is

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$R_1 < R_2 < R_3$

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(C) According to Ohm's law, $V = IR$, which implies $I = V/R$ or $R = V/I$.In the given $I-V$ graph, the slope of the line represents $I/V$, which is equal to $1/R$.Therefore, the slope of the graph is inversely proportional to the resistance $(Slope \propto 1/R)$.From the figure, the slope of the line for $R_1$ is the greatest, followed by $R_2$, and then $R_3$ (i.e., $Slope_1 > Slope_2 > Slope_3$).Since the slope is inversely proportional to resistance, a higher slope indicates a lower resistance.Thus, $R_1 < R_2 < R_3$.

$A$ student carries out an experiment and plots the $V-I$ graph of three samples of nichrome wire with resistances $R_1, R_2$ and $R_3$ respectively (Figure). Which of the following is true?

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