$A$ spring of force constant $k$ is cut into lengths of ratio $1:2:3$. They are connected in series and the new force constant is $k'$. Then they are connected in parallel and the force constant is $k''$. Then $k':k''$ is

  • A
    $1:11$
  • B
    $1:14$
  • C
    $1:16$
  • D
    $1:9$

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