Show that the oscillations due to a spring are simple harmonic oscillations and obtain the expression of periodic time.
According to figure a block of mass $m$ fixed to a spring, which in turn is fixed to a rigid wall.
The block is placed on a friction less horizontal surface.
If the block is pulled on one side and is released it then executes a to and fro motion about a mean position.
Let $x=0$, indicate the position of the centre of the block when the spring is in equilibrium. The positions - A and + A indicate the maximum displacements to the left and the right of the mean position.
For spring Robert Hooke law, "Spring when deformed, is subject to a restoring force, the magnitude of which is proportional to the deformation or the displacement and acts is opposite direction."
Let any time $t$, if the displacement of the block from its mean position is $x$, the restoring force $\mathrm{F}$ acting on the block it
$\mathrm{F}(x)=-k x \quad \ldots$ $(1)$
Where $k$ is constant of proportionality and is called the spring constant or spring force constant.
Equation $(1)$ is same as the force law for $SHM$ and therefore the system executes a simple harmonic motion.
In the situation as shown in figure time period of vertical oscillation of block for small displacements will be
If two similar springs each of spring constant $K _{1}$ are joined in series, the new spring constant and time period would be changed by a factor
If a watch with a wound spring is taken on to the moon, it
How the period of oscillation depend on the mass of block attached to the end of spring ?
A spring is stretched by $0.20\, m$, when a mass of $0.50\, kg$ is suspended. When a mass of $0.25\, kg$ is suspended, then its period of oscillation will be .... $\sec$ $(g = 10\,m/{s^2})$