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Question

(C) The change in momentum $\Delta p$ is given by the impulse exerted by the gravitational force.The force acting on the ball is its weight,$F = mg$,w

Vedclass · Accepted Answer

weight of the ball $	imes$ total time of flight

Vedclass · Answer

(C) The change in momentum $\Delta p$ is given by the impulse exerted by the gravitational force.The force acting on the ball is its weight,$F = mg$,which acts downwards.The time for which this force acts is the total time of flight,$T = \frac{2v \sin 	heta}{g}$.According to the impulse-momentum theorem,the change in momentum is equal to the impulse,which is the product of the constant force and the time interval.$\Delta p = F 	imes T = (mg) 	imes T$.Therefore,the total change in momentum is equal to the weight of the ball multiplied by the total time of flight.

$A$ ball is thrown up at an angle with the horizontal. Then,the total change of momentum by the instant it returns to the ground is

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