A series combination of n_1 capacitors,each o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In series,the equivalent capacitance is $C_S = \frac{C_1}{n_1}$.Energy stored,$E_S = \frac{1}{2} C_S V_S^2 = \frac{1}{2} \left(\frac{C_1}{n_1}\rig

Vedclass · Accepted Answer

$\frac{16C_1}{n_1n_2}$

Vedclass · Answer

(D) In series,the equivalent capacitance is $C_S = \frac{C_1}{n_1}$.Energy stored,$E_S = \frac{1}{2} C_S V_S^2 = \frac{1}{2} \left(\frac{C_1}{n_1}\right) (4V)^2 = \frac{8 C_1 V^2}{n_1}$.In parallel,the equivalent capacitance is $C_P = n_2 C_2$.Energy stored,$E_P = \frac{1}{2} C_P V_P^2 = \frac{1}{2} (n_2 C_2) (V)^2 = \frac{n_2 C_2 V^2}{2}$.Given that $E_S = E_P$,we have:$\frac{8 C_1 V^2}{n_1} = \frac{n_2 C_2 V^2}{2}$.Solving for $C_2$:$C_2 = \frac{16 C_1}{n_1 n_2}$.

Similar Questions

Let $A = \{ x: x \in R, |x| < 1 \}$ and $B = \{ x: x \in R, |x - 1| \ge 1 \}$. If $A \cup B = R - D$,then the set $D$ is:

In the Victor-Meyer's test,the colours given by $1^o$,$2^o$ and $3^o$ alcohols are respectively:

Two coherent sources of intensity ratio $x^2$ interfere. In the interference pattern,which of the following relations is correct?

What is the molecular formula of the product formed when benzene is reacted with ethyl chloride in the presence of anhydrous aluminium chloride?

The resistance across $M$ and $N$ in the given figure is

Vedclass Test Series

Exam Paper Generator

Online Exam Module