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(B) Let $r$ be the distance from each vertex to the centre of the equilateral triangle.Electric potential $V$ at the centre is the scalar sum of poten

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The field is non-zero but potential is zero

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(B) Let $r$ be the distance from each vertex to the centre of the equilateral triangle.Electric potential $V$ at the centre is the scalar sum of potentials due to individual charges:$V = V_{2q} + V_{-q} + V_{-q} = \frac{k(2q)}{r} + \frac{k(-q)}{r} + \frac{k(-q)}{r} = \frac{k}{r}(2q - q - q) = 0$.Electric field $\vec{E}$ at the centre is the vector sum of electric fields due to individual charges. Since the charges are not equal in magnitude and are not symmetrically placed in a way that their vectors cancel out,the resultant electric field $\vec{E}$ at the centre is non-zero.Thus,the field is non-zero but the potential is zero.

Three charges $2q, -q, -q$ are located at the vertices of an equilateral triangle. At the centre of the triangle:

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