$A$ semicircular sheet of metal of diameter $28 \, cm$ is bent into an open conical cup. The capacity of the cup (taking $\pi = \frac{22}{7}$) is (in $cm^3$):

$A$ large cube is formed from the material obtained by melting three smaller cubes of sides $3\, cm$,$4\, cm$,and $5\, cm$ respectively. What is the ratio of the total surface areas of the smaller cubes to the large cube?

The sum of the radius of the base and the height of a solid cylinder is $37\, m$. If the total surface area of the solid cylinder is $1628\, m^2$,then the circumference of its base and the volume of the cylinder are:

From a solid right circular cylinder with height $10 \ cm$ and radius of the base $6 \ cm$,a right circular cone of the same height and base is removed. The volume (in $cm^3$) of the remaining solid is

The material of a cone is converted into the shape of a cylinder of equal radius. If the height of the cylinder is $5\, cm$,the height of the cone is........$cm$.

If a cube with its edge $6 \ cm$ is melted and smaller cubes with edge $2 \ cm$ each are formed,then how many cubes are formed?