If a cube with its edge 6 cm is melted and s | vedclass

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(C) The volume of a cube is given by the formula $V = a^3$,where $a$ is the edge length.The volume of the original cube with edge $6 \ cm$ is $V_1 = (

Vedclass · Accepted Answer

$27$

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(C) The volume of a cube is given by the formula $V = a^3$,where $a$ is the edge length.The volume of the original cube with edge $6 \ cm$ is $V_1 = (6 \ cm)^3 = 216 \ cm^3$.The volume of each smaller cube with edge $2 \ cm$ is $V_2 = (2 \ cm)^3 = 8 \ cm^3$.The number of smaller cubes formed is the ratio of the total volume to the volume of one smaller cube:$	ext{Number of cubes} = \frac{V_1}{V_2} = \frac{216}{8} = 27$.Alternatively,using the ratio of edges:$	ext{Number of cubes} = \left(\frac{	ext{Original edge}}{	ext{New edge}}ight)^3 = \left(\frac{6}{2}ight)^3 = 3^3 = 27$.

If a cube with its edge $6 \ cm$ is melted and smaller cubes with edge $2 \ cm$ each are formed,then how many cubes are formed?

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