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(C) Given: $r + h = 37\, m$ and Total Surface Area $(TSA) = 2\pi r(r + h) = 1628\, m^2$.Substituting the value of $(r + h)$ in the $TSA$ formula:$2

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$44\, m; 4620\, m^3$

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(C) Given: $r + h = 37\, m$ and Total Surface Area $(TSA) = 2\pi r(r + h) = 1628\, m^2$.Substituting the value of $(r + h)$ in the $TSA$ formula:$2 	imes \frac{22}{7} 	imes r 	imes 37 = 1628$$r = \frac{1628 	imes 7}{2 	imes 22 	imes 37} = \frac{1628 	imes 7}{1628} = 7\, m$.Since $r + h = 37$,then $h = 37 - 7 = 30\, m$.Circumference of the base $= 2\pi r = 2 	imes \frac{22}{7} 	imes 7 = 44\, m$.Volume of the cylinder $= \pi r^2 h = \frac{22}{7} 	imes 7^2 	imes 30 = 22 	imes 7 	imes 30 = 4620\, m^3$.Thus,the circumference is $44\, m$ and the volume is $4620\, m^3$.

The sum of the radius of the base and the height of a solid cylinder is $37\, m$. If the total surface area of the solid cylinder is $1628\, m^2$,then the circumference of its base and the volume of the cylinder are:

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