$A$ seconds pendulum clock has a steel wire. The clock shows correct time at $25^{\circ} C$. How many seconds does the clock lose or gain in one week,when the temperature is increased to $35^{\circ} C$? (Given: $\alpha_{\text{steel}} = 1.2 \times 10^{-5} /^{\circ} C$)

  • A
    $321.5$
  • B
    $3.828$
  • C
    $82.35$
  • D
    $36.28$

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Similar Questions

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